This is a port of the following article.

科学するミックスボイス 2: TA筋とCT筋|moniはじめに 第 2 章では TA 筋と CT 筋が及ぼす声の周波数および声質について論じます。第 1 章を読んでいない方は先にご覧ください。 この章では大学 1 年程度の数学を扱います。使うのは常微分方程式と行列計算くらいなので、数学や物理が得意な高校生であれば読めるくらいの内容かと思います。 1. 質量-ばね-ダンパー系 (Mass-spring-damper model) まずは下準備として質量-ばね-ダンパー系について簡単に触れます。ばねはフックの法則に従い$${-kx}$$の力が質量に作用します。ダンパーは質量の速度に比例する抵抗力が生じ$${-c\dot{x}}$$note(ノート)

Introduction

Part 2 discusses how the TA and CT muscles affect vocal frequency and quality. If you have not read Part 1, please read it first.

A Scientific Approach to Mixed Voice 1. Anatomy and PhysiologyThis is a port of the following article. When I asked an AI, “How can I learn to sing in mixed voice?”, it replied that…moni's page

This part uses mathematics at roughly the level of a first-year university course. It involves little more than ordinary differential equations and matrix calculations, so I think a high-school student who is comfortable with mathematics and physics should be able to follow it.

1. Mass–Spring–Damper Model

As preparation, we will briefly review the mass–spring–damper model. A spring obeys Hooke's law and exerts a force kx-kx on the mass. A damper produces a resistive force proportional to the velocity of the mass and exerts a force cx˙-c\dot{x}.

Mass–spring–damper model
Mass–spring–damper model
Mass–spring–damper model (from Wikipedia)

If the external force acting on this system is FextF_\text{ext}, its equation of motion is

mx¨=kxcx˙+Fext.m \ddot{x} = -kx -c\dot{x} + F_\text{ext}.

Rearranging gives the standard form

x¨+2ζω+ω2x=u,\ddot{x} + 2\zeta \omega + \omega^2x = u,

where

  • ω=km\omega = \sqrt{\dfrac{k}{m}} is the natural angular frequency in the undamped case,
  • ζ=c2mk\zeta = \dfrac{c}{2\sqrt{mk}} is the damping ratio, and
  • u=Fextmu = \dfrac{F_\text{ext}}{m}.

In the homogeneous case Fext=0F_\text{ext}=0, this ordinary differential equation can be solved explicitly, giving the general solution x=x(t)x=x(t)

x(t)=Aeωt(ζ+ζ21)+Beωt(ζζ21).x(t) = Ae^{-\omega t \left( \zeta + \sqrt{\zeta^2 - 1} \right)} + Be^{-\omega t \left( \zeta - \sqrt{\zeta^2 - 1} \right)}.

The behavior of x(t)x(t) depends on how ζ\zeta compares with 11. In the vocal-fold model, however, the effect of the damper is small enough to be treated as a perturbation—otherwise phonation could not continue—so we consider ζ1\zeta \ll 1. Then ζ21\sqrt{\zeta^2-1} is imaginary and

x(t)=Ceζωtcos(1ζ2ωt+ϕ).x(t) = Ce^{-\zeta\omega t} \cos(\sqrt{1-\zeta^2} \omega t + \phi).

In particular, comparison with the unperturbed simple harmonic motion x(t)=Ccos(ωt+ϕ)x(t) = C \cos(\omega t + \phi) for c=0c=0 shows that the perturbation reduces the frequency by a factor of 1ζ2\sqrt{1 - \zeta^2} and introduces exponential decay eζωte^{-\zeta \omega t}.

2. A Physical Model of the Vocal Folds

2-1. Cover–Body Model

One physical model of the vocal folds is the Cover–Body Model, proposed by Minoru Hirano in 1974. As shown below, it treats the vocal folds as two layers, the cover and body, connected by a spring, with each layer following a mass–spring–damper model.

Cover–body model
Cover–body model
From B. Story, "An overview of the physiology, physics and modeling of the sound source for vowels"

The equations of motion for the cover and body are

mcx¨c=rcx˙ckcxckcb(xcxb)=Fc(t)mbx¨b=rbx˙bkbxbkcb(xbxc)=Fb(t).\begin{aligned} m_c\ddot{x}_c &= -r_c\dot{x}_c-k_cx_c-k_{cb}(x_c - x_b) = F_c(t) \\ m_b\ddot{x}_b &= -r_b\dot{x}_b-k_bx_b-k_{cb}(x_b - x_c) = F_b(t). \end{aligned}

Most of the notation should be self-explanatory, but kcbk_{cb} is the spring constant of the spring connecting the cover and body. Setting x=(xcxb)x=\begin{pmatrix} x_c \\ x_b \end{pmatrix} and rewriting the equations using vectors and matrices gives the standard form

Mx¨+Rx˙+Kx=F(t),M\ddot{x} + R\dot{x} + Kx = F(t),

where

  • M=(mc00mb)M=\begin{pmatrix} m_c & 0 \\ 0 & m_b \end{pmatrix},
  • R=(rc00rb)R=\begin{pmatrix} r_c & 0 \\ 0 & r_b \end{pmatrix},
  • K=(kc+kcbkcbkcbkb+kcb)K=\begin{pmatrix} k_c + k_{cb} & -k_{cb} \\ -k_{cb} & k_b + k_{cb} \end{pmatrix}, and
  • F(t)=(Fc(t)Fb(t))F(t)=\begin{pmatrix} F_c(t) \\ F_b(t) \end{pmatrix}.

2-2. Natural Frequencies

As discussed above, RR has only a small enough effect to be regarded as a perturbation, so R0R \approx 0. In the homogeneous case F(t)=0F(t)=0, the natural frequencies are of interest as the most efficient pitches at which the system can continue oscillating without an external force. The equation of motion becomes

Mx¨+Kx=0.M\ddot{x} + Kx = 0.

Assuming that a Fourier transform lets us represent the motion as a superposition of waves with different angular frequencies, it is enough to ask whether each angular frequency satisfies this equation. Assume a harmonic oscillation v(t)=veiωt,vC2v(t) = v e^{i \omega t}, \, v \in \mathbb{C}^2 and substitute it into the equation:

ω2Mveiωt+Kveiωt=0(Kω2M)v=0.\begin{align*}-\omega^2Mv e^{i \omega t} +Kve^{i \omega t} &= 0 \\\therefore (K - \omega^2 M)v &= 0.\end{align*}

Thus, ω2\omega^2 and vv are respectively an eigenvalue and eigenvector of M1KM^{-1}K. Setting λ=ω2\lambda = \omega^2, a nontrivial solution exists when det(KλM)=0\det(K - \lambda M) = 0, so

det(kc+kcbλmckcbkcbkb+kcbλmb)=0    λ2(ωc2+ωb2)λ+ωc2ωb2κ2=0    λ±=ω±2=ωc2+ωb2±(ωc2ωb2)2+4κ22,\begin{align*}& \det \begin{pmatrix} k_c + k_{cb} - \lambda m_c & -k_{cb} \\ -k_{cb} & k_{b} + k_{cb} - \lambda m_b \end{pmatrix} = 0 \\\iff & \lambda^2 - (\omega_c^2 + \omega_b^2) \lambda + \omega_c^2 \omega_b^2 - \kappa^2 = 0 \\\iff & \lambda_\pm = \omega_\pm^2 = \dfrac{\omega_c^2 + \omega_b^2 \pm \sqrt{(\omega_c^2-\omega_b^2)^2 + 4 \kappa^2}}{2},\end{align*}

where

  • ωc2=kc+kcbmc\omega_c^2 = \dfrac{k_c + k_{cb}}{m_c},
  • ωb2=kb+kcbmb\omega_b^2 = \dfrac{k_b + k_{cb}}{m_b}, and
  • κ2=kcb2mcmb\kappa^2 = \dfrac{k_{cb}^2}{m_cm_b}.

In particular, 0<ω2<ω+20 < \omega_-^2 < \omega_+^2. This means that the vocal folds produce sounds at two different pitches. Of these, ω\omega_- corresponds to the fundamental frequency f0f_0 of the voice, multiplied by 2π2\pi. We will verify this in the next subsection.

2-3. Eigenvectors

Let the corresponding eigenvector be v=(vcvb)v = \begin{pmatrix} v_c \\ v_b \end{pmatrix}. From (Kω2M)v=0(K - \omega^2M)v=0,

vbvc=kc+kcbω2mckcb=ωc2ω2κmcmb,\dfrac{v_b}{v_c} = \dfrac{k_c + k_{cb} - \omega^2m_c}{k_{cb}} = \dfrac{\omega_c^2 - \omega^2}{\kappa} \sqrt{\dfrac{m_c}{m_b}},

and in particular vbvcR\dfrac{v_b}{v_c} \in \mathbb{R}. Considering the sign of this value gives

ωc2ω2=12{(ωc2ωb2)2+4κ2+(ωc2ωb2)}>0ωc2ω+=12{(ωc2ωb2)2+4κ2(ωc2ωb2)}<0.\begin{align*}\omega_c^2 - \omega_-^2 &= & \dfrac12 & \left\lbrace \sqrt{(\omega_c^2 - \omega_b^2)^2 + 4\kappa^2} + (\omega_c^2 - \omega_b^2) \right\rbrace & &> 0 \\\omega_c^2 - \omega_+ &= & - \dfrac12 &\left\lbrace \sqrt{(\omega_c^2 - \omega_b^2)^2 + 4\kappa^2} - (\omega_c^2 - \omega_b^2) \right\rbrace & &< 0. \\\end{align*}

Therefore, when ω=ω\omega=\omega_-, vcv_c and vbv_b are in phase: the cover and body oscillate in the same direction. When ω=ω+\omega=\omega_+, they are out of phase and oscillate in opposite directions. The frequency at which the cover and body oscillate together produces the greater amplitude, and therefore the louder sound, so it corresponds to the fundamental. Its value f0f_0 is

f0=12πωc2+ωb2(ωc2ωb2)2+4κ22.f_0 = \dfrac{1}{2\pi}\sqrt{\dfrac{\omega_c^2 + \omega_b^2 - \sqrt{(\omega_c^2-\omega_b^2)^2 + 4 \kappa^2}}{2}}.

2-4. Voice Quality

Define voice quality Q(0,1]Q \in \left(0, 1 \right] by

Q:=ωω+.Q := \dfrac{\omega_-}{\omega_+}.

The following explains why this can be treated as a measure of voice quality.

Let D=(ωc2ωb2)2+4κ2D = \sqrt{(\omega_c^2 - \omega_b^2)^2+4\kappa^2} be the discriminant of the characteristic equation. Since ω+2=ω2+D\omega_+^2 = \omega_-^2+D,

Q=11+D/ω2.Q = \dfrac{1}{\sqrt{1 + D / \omega_-^2}}.

The value ω\omega_- is the frequency of the pitch we want to sing, so it cannot be changed. Consequently, QQ is determined by the discriminant DD and decreases monotonically with DD. The value DD is determined by the detuning ωcωb|\omega_c - \omega_b| and the cover–body coupling κ2=kcb2mcmb\kappa^2 = \dfrac{k_{cb}^2}{m_cm_b}. In particular, D2κD \ge 2\kappa, with equality when ωc=ωb\omega_c = \omega_b, giving the inequality

QQmax:=11+2κ/ω2.Q \le Q_{\max} := \dfrac{1}{\sqrt{1 + 2\kappa/\omega_-^2}}.

Finally, to see why less detuning improves voice quality, consider the interference between the two sounds with ω=ω±\omega = \omega_\pm:

Acos(ωt)+Bcos(ω+t)=(AB)cos(ωt)+B(cos(ωt)+cos(ω+t))=(AB)cos(ωt)+2Bcos(ω+ω2t)cos(ω++ω2t).\begin{align*}& A\cos(\omega_-t) + B\cos(\omega_+t) \\ = & (A-B)\cos(\omega_-t) + B \left( \cos(\omega_-t) + \cos(\omega_+t) \right) \\= & (A-B)\cos(\omega_- t) + 2B\cos\left(\dfrac{\omega_+ - \omega_-}{2}t \right) \cos\left( \dfrac{\omega_++\omega_-}{2}t \right).\end{align*}

Here ABA \ge B because the pitch at which the cover and body move in phase sounds louder. In the second term, ωˉ=ω++ω2\bar{\omega}=\dfrac{\omega_+ + \omega_-}{2} can be interpreted as the pitch, while Δω=ω+ω2\Delta \omega = \dfrac{\omega_+ - \omega_-}{2}—or more precisely, 2Bcos(Δωt)2B\cos(\Delta \omega t)—represents amplitude modulation. The smaller the difference between ω\omega_- and ω+\omega_+, the closer the sound is to a clean sine wave. Since ω+2=ω2+D\omega_+^2 = \omega_-^2+D, this is again achieved when the detuning ωcωb|\omega_c - \omega_b| is small.

Thus, Q(0,1]Q \in \left(0, 1 \right] can be interpreted as a physical measure of voice quality. More important than QQ itself, however, is the property that QQ increases as the detuning ωcωb|\omega_c - \omega_b| decreases.

3. TA and CT Muscles

After all that manipulation of equations, the physical quantities we can actually adjust during phonation are essentially limited to kck_c and kbk_b. These spring constants are determined by the stiffness, or strength of the restoring force, of the respective springs. Put simply:

  • Contracting the TA muscle stiffens the body, increasing kbk_b.
  • Contracting the CT muscle stiffens the cover, increasing kck_c.

The correspondence between the adjusted vocal folds and the voice they produce can therefore be represented by the map F:(kc,kb)(f0,Q)F:(k_c, k_b) \mapsto (f_0, Q). To review the physical quantities involved:

  • f0=12πωc2+ωb2(ωc2ωb2)2+4κ22f_0 = \dfrac{1}{2\pi}\sqrt{\dfrac{\omega_c^2 + \omega_b^2 - \sqrt{(\omega_c^2-\omega_b^2)^2 + 4 \kappa^2}}{2}}
  • Q=11+(ωc2ωb2)2+4κ2(2πf0)2Q = \dfrac{1}{\sqrt{1 + \dfrac{\sqrt{(\omega_c^2 - \omega_b^2)^2+4\kappa^2}}{(2 \pi f_0)^2}}}
  • ωc=kc+kcbmc\omega_c = \sqrt{\dfrac{k_c + k_{cb}}{m_c}}
  • ωb=kb+kcbmb\omega_b = \sqrt{\dfrac{k_b + k_{cb}}{m_b}}
  • κ=kcbmcmb\kappa = \dfrac{k_{cb}}{\sqrt{m_cm_b}}

A song is a function that assigns a pitch f=f(t)f = f(t) to each time tt. To sing well, then, is to choose a path γ=γ(t)\gamma = \gamma(t) through the (kc,kb)(k_c, k_b) domain such that the first component of its image Fγ(t)F \circ \gamma(t) equals f(t)f(t) and the second component is maximized, then control the contractions of the TA and CT muscles along γ\gamma.

Producing a higher voice—increasing f0f_0—means increasing at least one of ωc\omega_c and ωb\omega_b. The ideal singing technique uses the TA and CT muscles in balance, raising both while maintaining ωcωb\omega_c \approx \omega_b. Then

QQmax=11+2κ(2πf0)21(f0+).Q \approx Q_{\max} = \dfrac{1}{\sqrt{1 + \dfrac{2\kappa}{(2 \pi f_0)^2}}} \to 1 \qquad (f_0 \to +\infty).

Intuitively, compared with the cover–body coupling κ\kappa, the stiffness of each of the cover and body layers becomes dominant. As a result, the characteristic equation with two distinct natural frequencies becomes degenerate. This agrees with experience: when properly trained singers balance these muscles, their high notes resonate most strongly.

Now consider contracting only one of the muscles. If only the TA muscle contracts, the stiffened body resists the vibration of the cover, producing a constricted sound and reducing voice quality. If only the CT muscle contracts, the CT muscle oscillates rapidly while the TA muscle remains relaxed, producing a thin sound and again reducing voice quality.

In practice, voice quality also has aspects that QQ alone cannot measure. For example, trying to engage the CT muscle in a low chest voice causes the TA muscle to relax more than necessary, producing a weak, thin sound. It is therefore essential to maintain TA dominance, particularly at the low end of the chest register. The discussion here is a mathematical observation that, in the middle and high ranges around the passaggio, using both muscles in balance rather than relying on only one allows smoother, cleaner transitions between pitches.

Conclusion

If you are not accustomed to mathematics, thank you especially for making it this far. Only Part 3, which discusses formants, remains. Unfortunately, it requires still more advanced mathematics. Once you have prepared yourself, take a look when you have some energy to spare.

A Scientific Approach to Mixed Voice 3. Formant TuningThis is a port of the following article. In this final part, we will interpret mathematically how formants and vocal fr…moni's page